J.R. S. answered 01/22/22
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a) Eº = 1.066 - (-0.744) = 1.81 V
b) Br2 + 2e- ==> 2Br- Eº = 1.066 V (cathode)
Cr ==> Cr3+ + 3e- Eº = -0.744 V (anode)
c) 3Br2 + 2Cr ==> 6Br- + 2Cr3+