Inactive Tutor answered 01/22/22
If a quadrilateral is equilateral it is rhombus. let there be rhombus ABCD.
AB = BC = CD = AD
with diagonals AC & BD
let X be the intersection of diagonals
there is isosceles triangle ABC, with BX perpendicular to AC (prove this by congruence theorems on your own), BD is extension of BX so AC is perpendicular to BD.