Given that 6.9 moles of carbon monoxide gas are present in a container of volume 34.5 L, what is the pressure of the gas (in atm) if the temperature is 62°C

Answer 1

Ideal gas law:

PV = nRT

P = pressure in atm = ?

V = volume in L = 34.5 L

n = moles = 6.9 moles

R = gas constant = 0.0821 Latm/Kmol

T = temperature in K = 62 + 273 = 335K

Substituting and solving for P, we have ...

P = nRT/V

P = (6.9)(0.0821)(335) / 34.5

P = 5.5 atm (2 sig. figs.)