Jon S. answered 01/21/22
Patient and Knowledgeable Math and English Tutor
The 99% confidence level corresponds to a the z-score at a probability of 99.5 = 2.58
The sample size (n) = (z-score * standard deviation/margin of error)^2 =
(2.58 * 6.4/0.45)^2 = 1346.4 ~ 1347
So you would need 1347 - 40 = 1317 more bacteria