Lander M. answered 01/21/22
Attentive STEM/Test Prep Tutor w/ 15 Yrs Experience (2400 SAT/36 ACT)
Let's call the population proportion of yellow eggs p = .32. For sufficiently large sample sizes, the sampling distribution for the sample proportion is approximately normally distributed, with mean p and standard deviation sqrt(pq/n), where q = 1-p and n is the sample size. Thus we calculate the standard deviation to be sqrt(.32*.68/46) = .069.