J.R. S. answered 01/19/22
Ph.D. University Professor with 10+ years Tutoring Experience
Let's look at the balanced equation for the reaction taking place:
2C8H18 + 25O2 ==> 16CO2 + 18H2O ... balanced equation for combustion of octane (C8H18)
We know we obtained 424.3 g CO2 and195.3 g of H2O. We know we started with 137.4 g of C8H8. By the law of conservation of mass, we can find the mass of O2 used. Assuming no losses, the mass of the reactants must equal the mass of the products
424.3 g + 195.3 g = 619.6 g total mass of products
619.6 g - 137.4 g = 482.2 g O2 used