A 23.0g sample of silver nitrate AgNO3, is added to a sample of distilled water to produce a 45.7 solution.

Question

A) What is the molar concentration of the solution?

B) You wish to make 500.0mL of a 0.600M solution. What volume of the above solution will you dilute?

Answer 1

Is that supposed to be 45.7 mls of solution? If so, here's how to do the problem.

Molar mass AgNO3 = 169.9 g /mol

23.0 g AgNO3 x 1 mol / 169.9 g = 0.135 moles AgNO3

45.7 mls x 1 L / 1000 mls = 0.0457 L

Molarity of solution = moles/L = 0.135 moles / 0.0457 L = 2.96 M

To make 500.0 ml of 0.600 M from the above solution...

V1M1 = V2M2

(x ml)(2.96 M) = (500 ml)(0.600 M)

x = 101 mls (3 sig. figs.)