Lydia F. answered 01/18/22
Doctor of Pharmacy Specializing in Chemistry (10+ years experience)
Hi Anna!
This is a method of weighing called "weighing by difference". In weighing by difference, the weight of the material (in this case, water) is equal to the difference between the two weights of the beaker before and after the water was added.
What this looks like mathematically is:
(Weight of the beaker + water) = (weight of the empty beaker) + (weight of water)
If we rearrange that, we get the "difference" and thus can solve for the weight of water:
(Weight of water) = (weight of the beaker + water) - (weight of the empty beaker)
Let's apply this to your problem!
Givens:
Weight of empty beaker = 251.70 g
Weight of beaker + water = 268.309 g
Calculations:
Weight of water = (weight of the beaker + water) - (weight of the empty beaker)
Weight of water = 268.309 g - 251.70 g
Weight of water = 16.609 g
Now, let's talk sig figs.
When adding or subtracting, we base our significant figures on the least number of decimal places. The weight of the beaker with the water (268.309) has three decimal places while the weight of the beaker without water (251.70) has two decimal places.
Therefore, our final answer will have two decimal places: 16.61 g!
Hope this helps! Feel free to contact me if you have anymore chemistry questions. :)