What volume of 1.25M hydroiodic acid is needed to neutralize 37.45g of magnesium hydroxide?

Question

Balanced chemical equation is 2HI + Mg(OH)2 -> MgI2 + 2H2O

Answer 1

2HI + Mg(OH)₂ -> MgI₂ + 2H₂O ... balanced equation for the reaction taking place

molar mass Mg(OH)₂ = 58.32 g / mol

moles Mg(OH)₂ present = 37.45 g x 1 mol / 58.32 g = 0.6421 moles Mg(OH)₂

moles HI needed = 0.6421 mols Mg(OH)₂ x 2 mols HI / mol Mg(OH)₂ = 1.284 mols HI needed

volume HI needed = 1.284 mols HI x 1 L / 1.25 mols = 1.027 L = 1.03 L HI needed (3 sig. figs.)