The first number is 6 more than the second number. The sum of twice the second number and three times the first number , equals 33. What is the sum of these two numbers

Answer 1

F = 6 + S

S - F = -6

2S + 3F = 33

2S - 2F = -12

subtract to eliminate one variable

5F = 45

F = 45/5 = 9

first number = 9

second number = S = 9-6 = 3