Calculate the amount of energy required to increase the temperature of 1 mol of Fructose by 5 degrees

Answer 1

Whenever an object is heated, the heat required q, for the mass of the substance m, the object's heat capacity c, and the change in temperature are related by their products.

q = m c Δ T

The mass of 1 mol of fructose is equal to:

m = 180.16 g/mol • 1mol = 180.16 g

The specific heat capacity of fructose is a difficult find, since it probably is going to be in a water solution, in which case the amount of water would affect the numberical value of the heat capacity.

For pure fructose, 230.50 J/K•mol and 201.00 J/K•mol are both listed on Fructose (CAS 7660-25-5) - Chemical & Physical Properties by Cheméo (chemeo.com)

Whichever value of c you decide to go with, make sure it is approved by your teacher or lab assistant.

Lastly, for the change in temperature ΔT, simply use 5° provided the measurement is in Celsius or Kelvin. If the temperature is Fahrenheit, a change of units will be necessary.

Hope that helps!

Best wishes,

Chris

Answer 2

We need to know the specific heat for fructose. Looking it up, I find it to be 201 J/molº.

Therefore, to raise the temperature of 1 mol of solid fructose by 5º, it would take...

201 J/molº x 5º = 1005 J

Answer 3

Hi Hayla D.,

This is not something that you would try to calculate from first principles. You simply don't have information on crystal structure, etc.

So try looking the heat capacity of fructose up. You will find some quite differing values (~230 and ~210 J mol^-1 K^-1) in one listing, and a single value (0,2748 cal / kg • deg) in another listing (https://en.baker-group.net/raw-materials-and-semi-finished-products/raw-materials-and-ingredients/glucose-fructose-sugar-and-invert-sugar-ck.html). You will need to reconcile these, bearing in mind that they MAY represent for anhydrous and hydrate forms of fructose (get formulae, calculate molar masses).

Lastly, there is the possibility that experimentally determined values may be on crystalline or amorphous materials; that will also make (quite) a difference.

-- Cheers, -- Mr. d.