How many moles of SO2 are required to convert 6.8 g of HaS according to the following reaction? (0.10 g S02) 2 HaS + S02 - 3 S + 2 H20

Answer 1

2H₂​S + SO_2​==> 3S + 2H₂​O I'm pretty sure this is the balanced equation that you meant to submit.

molar mass H₂S = 34.1 g/mol

6.8 g H₂S x 1 mol H₂S / 34.1 g x 1 mol SO₂ / 2 mol H₂S = 0.0997 moles = 0.10 mols SO₂ needed

Answer 2

This question doesn't make sense because Ha is not an elemental symbol. Ha's molar mass is required to solve the question, and that molar mass would be on the periodic table. Ha is not on the periodic table. Perhaps your professor made a typo, and meant to say:

Hf=Hafnium