A wheel with diameter 25 in. is rotating 11°/sec. Find the linear speed and round to 3 decimal places.

Question

How would I solve this?

Answer 1

A wheel with diameter 25 in. is rotating 11°/sec. Find the linear speed and round to 3 decimal places.

How would I solve this?

The wheel must move along a surface in order to have a linear speed.

The rate of rotation is 11°/sec. What speed is that along the surface?

Well, the definition of Π is (circumference of circle) / (diameter of circle). So, C = Πd

C = 3.1415926*25" = 78.539815" and a full turn [that is, circumference) is 360º

The wheel moves at 11º/sec.

(11º/sec)*1

(11º/sec)*(78.539815' / 360º)

2.400"/sec

Answer 2

2πr is circumference length, 2π*25 in.

11 degrees is 11/360 th of full circle for full circumference

point on circumference travels (11/360)*2π*25 inches in one second.