Larry spent 1/2 of his money on a camera and another 1/8 on a radio. The camera cost $120 more than the radio. How much money did he have at first?

Answer 1

C = 120 + R

C = M/2

R = M/8

M/2 = 120 + M/8

multiply both sides by 8 to remove the fractions

4M = 960 + M

3M = 960

M = $320 is how much money Larry had to start

He spent half of it, $160 on the camera

He spent 1/8 of it, $40 on the radio

That's $120 more on the camera than on the radio