How do i solve this

Question

it is 3x+10=5x and it is segmant addition, determine the numerical length of 

AC

Answer 1

Point B is on line segment \ overline AC . Given AB=2x+10, BC=x, and AC=5x, determine the numerical length of \ overline AC= ?? (How do i solve this: it is 3x+10=5x and it is segmant addition, determine the numerical length of AC)

Detailed Solution:

AB = 2x + 10 BC = x AC = 5x

A======================================================B==============C

AC = AB + BC

(5x) = (2x + 10) + (x)

5x = 3x + 10

5x – 3x = 10

2x = 10

x = 5

Therefore:

AB = 2x + 10 ==> AB = 2(5) + 10 ==> AB = 10 + 10 ==> AB = 20

BC = x ==> BC = (5) ==> BC = 5

AC = 5x ==> AC = 5(5) ==> AC = 25

Check: AC = AB + BC ==> 25 = 20 + 5 ==> 25 = 25

Answer 2

Please try to be more clear wit the question. But, as far as the equation is concerned,

we can say that

3x +10 = 5x

=> 2x = 10

=> x = 5

So, now you possibly your AB and BC are in the form of ax +b.

Substitute x = 5 and then add them to get AC

e.g.

AB = ax + b

BC = cx + d

AC = AB + BC

AC = (a+c)x + b + d

AC = 5(a+c) + b + d