J.R. S. answered 01/10/22
Ph.D. University Professor with 10+ years Tutoring Experience
4Au(s) + 8NaCN(aq) + O2 (g) + 2H2O(l) → 4NaAu(CN)2 (aq) + 4NaOH(aq) ... balanced equation
molar mass NaCN = 49.0 g / mol
atomic mass Au = 197 g / mol
(a). 25.0 g NaCN x 1 mol NaCN / 49.0 g x 4 mol Au / 8 mol NaCN x 197 g Au / mol = 50.3 g Au
(b). 50.3 g / 150.0 g (x100%) = 33.5%
E C.
thank you01/10/22