J.R. S. answered 01/07/22
Ph.D. University Professor with 10+ years Tutoring Experience
1a). V1M1 = V2M2
V1 = initial volume = 975.0 ml
M1 = initial concentration = 0.850 mol//L
V2 = final volume = ?
M2 = final concentration = 0.375 mol/L
(975 ml)(0.850 mol/L) = (V2)(0.375 mol/L)
V2 = 2210 mls
1b). you would have to add 2210 - 975 = 1235 mls of water
2). 4.0 L x 0.72% WBC = 4.0 L x 0.0072 = 0.0288 L of leukocytes