J.R. S. answered 01/06/22
Ph.D. University Professor with 10+ years Tutoring Experience
Al2(SO4)3 ==> 2Al3+(aq) + 3SO42-(aq)
If you begin with 0.080 M Al2(SO4)3 you will end up with
0.08 x 2 Al3+ = 0.16 M Al3+
0.08 x 3SO42- = 0.24 M SO42-
Margie C.
asked 01/06/22Calculate the concentrations of the ion(s) indicated in each of the following solutions.
[Al^+3] and [SO4^-2] in 0.080 M Al2(SO4)3
J.R. S. answered 01/06/22
Ph.D. University Professor with 10+ years Tutoring Experience
Al2(SO4)3 ==> 2Al3+(aq) + 3SO42-(aq)
If you begin with 0.080 M Al2(SO4)3 you will end up with
0.08 x 2 Al3+ = 0.16 M Al3+
0.08 x 3SO42- = 0.24 M SO42-
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