Eric C. answered 12/29/21
Engineer, Surfer Dude, Football Player, USC Alum, Math Aficionado
Hi Victoria,
There are a couple ways to solve this. One includes using the law of cosines to find the height of the triangle, then using A = 1/2*b*h. The other uses Heron's formula to find it using the semi-perimeter.
I drew the triangle with 6 on the left, 6.8 on the right, and 8.8 as the base. I called the bottom left angle, which is formed by 8.8 and 6, as "theta". By law of cosines, we get:
6.82 = 62 + 8.82 - 2(6)(8.8)*cos(Θ)
46.24 = 113.44 - 105.6*cos(Θ)
-67.2 = -105.6*cos(Θ)
cos(Θ) = 0.636363
Θ = 50.48 deg
We can draw a perpendicular line segment from the top angle to the base and call it H. We can then state:
sin(Θ) = H / 6
sin(50.48) = H / 6
H = 4.63
So with a base of 8.8 and a height of 4.63, the area is 20.372.
Heron's formula is a bit more straightforward. First find the "semi-perimeter".
s = (a + b + c)/2
s = (6 + 6.8 + 8.8)/2
s = 10.8
Then just plug this into Heron's formula
A = sqrt(s*(s - a)*(s - b)*(s - c))
= sqrt(10.8*(10.8 - 6)*(10.8 - 6.8)*(10.8 - 8.8))
= sqrt(10.8*4.8*4*2)
= sqrt(414.72)
= 20.365
The slight difference in answers is due to rounding errors from the determination of Θ and H. I'm sure if I reported each to 5 or 6 decimals it would've been a much closer match. Both round to 20.4, though, so for the purpose of this question either method would be okay.
Hope this helps!
Victoria J.
Awesome confirming my answer of 20.4. Thank you!!12/29/21