Consider the following equilibrium: 2O3 (g) ↔ 3O2 (g) Keq = 36

Question

What is the concentration of O₃ when the equilibrium concentration of O₂ is 6.0 X 10 ^- 2 mol/L?

Select one:

a. 

6.0 X 10 ^- 2 mo/L

b. 

4.0 X 10 ^- 2 mol/L

c. 

9.0 X 10 ^- 2 mol/L

d. 

2.4 X 10 ^- 3 mol/L

Answer 1

2O₃ <==> 3O₂ K = 36

K = 36 = [O₂]³ / [O₃]² = (6x10^-2)³ / x²

36x² = 2.16x10^-4

x² = 6x10^-6

x = 2.45x10^-3 M = [O₃] = ANSWER D