Mark M. answered 03/15/15
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Retired Math prof with teaching and tutoring experience in trig.
cosθ = √(cosθ)
square both sides: cos2θ = cosθ
cos2θ - cosθ = 0
cosθ(cosθ - 1) = 0
cosθ = 0 or cosθ = 1
if cosθ = 0 and 0° ≤ θ ≤ 180°, then θ = 90°
if cosθ = 1 and 0° ≤ θ ≤ 180°, then θ = 0°
Solutions: 0°, 90°