
Jon S. answered 12/16/21
Patient and Knowledgeable Math and English Tutor
Ho: mu >= 50
Ha: mu < 50
z = (mean - mu)/(SD/sqrt(sample size)) = (48-50)/(4/sqrt(40)= -3.16
P(z < -3.16) = 0.001.
p-value = 0.001, which is less than alpha = 0.025, so would reject Ho (the worker's claim) and conclude the sample information is not consistent with the worker's claim.