Mark M. answered 12/15/21
Retired Math prof with teaching and tutoring experience in trig.
(1 - cos2θ) / sin2θ = (1 - (2cos2θ - 1)) / (2sinθcosθ) =
(2 - 2cos2θ) / (2sinθcosθ) = (1 - cos2θ) / (sinθcosθ) = sin2θ / (sinθcosθ) = sinθ / cosθ = tanθ
Mike O.
asked 12/14/21Verify the identity.
1−cos2𝜃/sin2𝜃 = tan𝜃
Please show workings.
Thank you.
Mark M. answered 12/15/21
Retired Math prof with teaching and tutoring experience in trig.
(1 - cos2θ) / sin2θ = (1 - (2cos2θ - 1)) / (2sinθcosθ) =
(2 - 2cos2θ) / (2sinθcosθ) = (1 - cos2θ) / (sinθcosθ) = sin2θ / (sinθcosθ) = sinθ / cosθ = tanθ
Mark M. answered 12/14/21
Mathematics Teacher - NCLB Highly Qualified
Use double-angle formula to convert.
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