Inactive Tutor answered 01/23/22
H0: µB1 = µB2 = µB3
Ha: The means are not equal.
ANOVA TABLE
| Source | SS | d.f. | MS = SS / d.f. |
| A | 123.0 | 2 | 61.5 |
| B | 532.1 | 2 | 266.05 |
| Fb = MSb/MSe = 26.55 | |||
| Error | 390.9 | 39 | 10.02 |
| Total | 1046.0 | 43 | p(>Fb) = 5.28 x 10-8 |
Devin S.
asked 12/14/21The partial ANOVA table below shows the results of an experiment to test the effect of two factors (A and B) on the yield in a production process. The levels of each factor were selected randomly from a larger set of levels.
(i) (2pt).Write Ho and Ha for testing factor B.
(ii) (4pt) B was significant from the F-test. Calculate the variance component for B.
(Use the formula sheet given to help you determine the F-test, if necessary.)
ANOVA TABLE
| Source | SS | d.f. | MS |
| A | 123.0 | 2 | |
| B | 532.1 | 2 | |
| Error | 390.9 | 39 | |
| Total | 1046.0 | 43 |
Inactive Tutor answered 01/23/22
H0: µB1 = µB2 = µB3
Ha: The means are not equal.
ANOVA TABLE
| Source | SS | d.f. | MS = SS / d.f. |
| A | 123.0 | 2 | 61.5 |
| B | 532.1 | 2 | 266.05 |
| Fb = MSb/MSe = 26.55 | |||
| Error | 390.9 | 39 | 10.02 |
| Total | 1046.0 | 43 | p(>Fb) = 5.28 x 10-8 |
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