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Question

For the following reaction, 0.456 moles of carbon monoxide are mixed with 0.387 moles of oxygen gas.

Carbon monoxide (g)+ oxygen (g) = Carbon dioxide (g)

What is the formula for the limiting reagent?

What is the maximum amount of carbon dioxide that can be produced?

 moles

Answer 1

2CO + O2 == 2CO2 …. balanced equation

An easy way to find limiting reactant is to divide moles of each reactant by its corresponding coefficient in the balanced equation.

For CO: 0.456 mol / 2 = 0.223

For O2 : 0.387 mol / 1 = 0.387

CO IS LIMITING

Max amount CO2 formed is determined by the limiting reactant. Thus …

0.456 mol CO x 2 mol CO2 / 2 mol CO = 0.456 mol CO2