How many moles of NH₃ form when 32.4 L of H₂ gas completely reacts at STP according to the following reaction? Remember 1 mol of an ideal gas has a volume of 22.4 L at STP N₂(g) + 3 H₂(g) → 2 NH₃(g)

Answer 1

Since temperature and pressure are constant, you can viw liters as though they were moles.

N₂(g) + 3 H₂(g) → 2 NH₃(g)

32.4 L H₂ x 2 L NH3 / 3 L H2 = 21.6 L NH3

21.6 L x 1 mol/ 22.4 L = 0.964 mols NH3

or …

32.4 L H2 x 1mol H2/22.4 L x 2 mol NH3/3 mol H2 = 0.964 mol NH3