Acid and bases/chemistry

Question

A solution is prepared by dissolving 0.312g of the strong acid HCI (MM=36.458g/mol) in enough water to make 0.458L of solution. Calculate the pH of the solution to 4 decimal places.

Answer 1

To find pH, we need to find [H+].

[H-] = mol/L0.312 g x 1 mol/36.45 g = 0.00856 mol

0.00856 mol/0.458 L = 0.0187 M

pH = - log .0187

pH = 1.73