Finding missing length of an odd shaped trapezoid

Question

My wife and I are interesting in purchasing a piece of land that is an odd-shaped Trapezoid. B1=129.98ft, B2=72.9ft, S1=445.36, S2=436.2. The area is approx 1.02 acres. Basically the lot is wider at the front and tapers in the back. The front=B1, the back=B2. I am trying to determine the approx width of the property at 200ft back. None of the angles are known and none are 90 degrees. Any help would be greatly appreciated!!

Answer 1

The lot is 44431.2 ft²

44431.2 = (0.5)(129.98 + 72.9)h, h being the height, here the depth of the lot.

88862.4 = 202.88h

438.005 ≈ h

The width of the lot decreases from 129.98 ft to 72.9 ft.

This is a decrease of 57.08. The decrease is a linear function of depth.

(200 / 438.005)(57.08) = 26.063

At 200 ft back the lot is 129.98 - 26.063 or 103.917 ft give or take an inch or two!