
David W. answered 12/11/21
Experienced Prof
a.) 4𝑥−5𝑦=8
x:intercept: ?
y: intercept: ?
x-intercept at y=0, so
4x = 8
solve for x
y-intercept at x=0, so
-5y = 8
solve for y
b.) 𝑦=𝑥^2−2𝑥−15
x:intercept: ?
y: intercept: ?
x-intercept at y=0, so
0 = x2 - 2x -15
0 = (x-5)(x+3)
solve for two values of x
y-intercept at x=0
y = -15