Raymond B. answered 12/11/21
Math, microeconomics or criminal justice
a) 1 meter
b) 406 meters = max height in 9 seconds
c) hits ground in 18.01 seconds
a) the constant term is the intitial height = 1 meter
b) complete the square
-5(t^2 - 18t + 81) + 1 + 81(5) = -5(t-9)^2 + 406
that's in vertex form with vertex = (9, 406) where t=9 seconds to reach the max 406 meters
c) set the equation = 0, 0 is ground level
use the quadratic equation for h, ignore the negative square root
-5t^2 +90t + 1 = 0
t = -90/-10 + (1/10)sqr(8100+20) =about 9+9.01 = 18.01 seconds to reach the ground