
Dayv O. answered 12/09/21
Caring Super Enthusiastic Knowledgeable Trigonometry Tutor
call cosx x, and sinx y
y4-x4=y2-x2
same as
(y2+x2)(y2-x2)=y2-x2
in this scheme, (y2+x2)=sin2x+cos2x
and sin2x+cos2x=1
left with (y2-x2)=y2-x2
Melissa M.
asked 12/09/21sin4(θ) - cos4(θ) = sin2 (θ) - cos2(θ)
Dayv O. answered 12/09/21
Caring Super Enthusiastic Knowledgeable Trigonometry Tutor
call cosx x, and sinx y
y4-x4=y2-x2
same as
(y2+x2)(y2-x2)=y2-x2
in this scheme, (y2+x2)=sin2x+cos2x
and sin2x+cos2x=1
left with (y2-x2)=y2-x2
Mark M. answered 12/09/21
Mathematics Teacher - NCLB Highly Qualified
cos4 θ = (1 - sin2 θ)2
Start with that.
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