J.R. S. answered 12/09/21
Tutor
5.0
(145)
Ph.D. University Professor with 10+ years Tutoring Experience
pH = -log [H+]
pH = -log 1.3x10-9
pH = 8.89
Lutumika F.
asked 12/09/21J.R. S. answered 12/09/21
Ph.D. University Professor with 10+ years Tutoring Experience
pH = -log [H+]
pH = -log 1.3x10-9
pH = 8.89
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