2 SIN THETA PLUS SQUADE ROOT OF3 EQUALS ZERO

Question

SOLVE THE EQUATIONS FOR ALL VALUES GREATER THAN OR EQUAL TO ZERO AND LESS THAN 360 DEGREES.

Answer 1

2 sin θ + √3 = 0

2 sin θ = -√3

sin θ = -√3 / 2

Can you locate on unit circle and answer?

Answer 2

2 sinΘ + sqrt(3) = 0 -> 2 sinΘ = -sqrt(3) -> sinΘ = -sqrt(3)/2

When sinΘ = sqrt(3)/2, Θ = 60°. The quandrants where sine is positive are the 1st and 2nd quadrants.

The quadrants where sine is negative are the 3rd and 4th quadrants.

Therefore Θ = 240° and 300°