J.R. S. answered 12/08/21
Ph.D. University Professor with 10+ years Tutoring Experience
Couple of ways to approach this problem.
(1). Percent composition
H2O = 2 H + 1 O = 2 g H + 16 g O = total of 18 g
%H = 2 g / 18 g (x100%) = 11.11% H
%O = 16 g / 18 g (x100%) = 88.89% O
If you have 100 g H2O, the amount of H and O is found as follows:
100 g H2O x 11.11% H = 11.11 g H
100 g H2O x 88.89% O = 88.89 g O
(2). gram -> mole -> gram
100 g H2O x 1 mol H2O / 18 g = 5.56 mols H2O
5.56 mols H2O x 2 mols H / mol H2O x 1 g H / mol H = 11.1 g H
5.56 mols H2O x 1 mol O / mol H2O x 16 g O / mol O = 88.9 g O

J.R. S.
12/08/21
Icee R.
Alright, I understand! Thank you for clarifying that.12/08/21
Icee R.
Thanks for solving it! If I were to ask, how were you able to get 5.56 mols for 100g of H20? I've tried breaking down 100g of H20 and got 5.55 mols (100/18.02g/mol of water) as a result.12/08/21