Melissa M.
asked • 12/08/21solve log x+ log (x+3) = 1
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2 Answers By Expert Tutors
Inactive Tutor answered • 12/08/21
Tutor
New to Wyzant
Assuming log(x) = log10(x)
log(x)+log(x+3) = 1
log(x(x+3)) = 1
Take both sides to power of 10
x2+3x = 101 = 10
x2+3x-10 = 0
(x-2)(x+5) = 0
x = 2,-5
Inactive Tutor answered • 12/08/21
Tutor
New to Wyzant
Assuming log(x) = log10(x)
log(x)+log(x+3) = 1
log(x(x+3)) = 1
Take both sides to power of 10
x2+3x = 101 = 10
x2+3x-10 = 0
(x-2)(x+5) = 0
x = 2,-5
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Inactive Tutor
Locate the law for the sum of logrithms.12/08/21