chemistry A question 6

Question

I need help with question 6, please! it asks "Iron has a specific heat capacity of 0.4490j/gdegreeC. An iron nail with a mass of 12.01 grams absorbs 16.18 joules of heat. If its initial temperature was 27.00degreeC, what is its final temperature?

Answer 1

Hey Melissa,

Use q = mC∆T

q = heat = 16.18 J

m = mass = 12.01 g

C = specific heat = 0.4490 J/gº

∆T = change in temperature = ?

Solve for ∆T ...

∆T = q / (m)(C) = 16.18 J / (12.01 g)(0.4490 J/gº)

∆T = 3.000º

This is the change in temperature and since the nail absorbs heat, we must add this to the initial temperature of the nail to get the final temperature. Thus..

27.00º + 3.000º = 30.00ºC = final temperature of the nail