What volume, in Liters, would 250. g of (NH4)2S04 occupy at STP?

Question

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Answer 1

If we assume the (NH₄)₂SO₄ was present as an ideal gas, then we can use the value of 1 mol of an ideal gas occupies 22.4 liters.

molar mass (NH₄)₂SO₄ = 132 g/mol

250 g x 1 mol / 132 g = 1.923 mols

1.923 mols x 22.4 L /mol = 43.08 L = 43.1 L (3 sig. figs.)