using molarity to find solute moles and solution volume

Question

Calculate the volume in milliliters of a 0.41 mol/L copper(II) sulfate solution that contains 300. mmol of copper(II) sulfate CuSO4. Round your answer to 2 significant digits.

Answer 1

0.41 mol / L = 0.41 mol / L x 1000 mmol / mol x 1 L / 1000 ml = 0.41 mmol / ml

0.41 mmol / ml (x ml) = 300 mmol

x = 732 mls = 730 mls (2 sig. figs.)