J.R. S. answered 12/04/21
Ph.D. University Professor with 10+ years Tutoring Experience
So, you are essentially charged with converting 0.0035 g/dL Mg2+ into milliequivalents (mEq) Mg2+ / L.
And you are correct that you need to do a series of conversions.
We have 0.0035 g / dL
Convert this to moles Mg / dL: 0.0035 g /dL x 1 mol Mg / 24.31 g = 0.00014397 moles Mg / dL
Convert this to moles Mg / L: 0.00014397 mols Mg / dL x 10 dL / L = 0.0014397 mols Mg / L
Convert this to mmoles Mg / L: 0.0014397 mols Mg / L x 1000 mmols / mol = 1.4397 mmol Mg / L
Finally, convert this to mEq / L: Since the valence on Mg is 2+, each mmole = 2 mEq, so we have...
1.4397 mmol / L x 2 mEq / mmol = 2.879 mEq/L = 2.9 mEq Mg2+ / L (2 sig. figs.)
(be sure to check my math)
Savannah N.
Thank you so much!12/04/21