J.R. S. answered 12/04/21
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2Al(s) + 3I2(s) ==> 2AlI3(s) ... balanced equation
Use the stoichiometry of the balanced equation along with dimensional analysis to find the theoretical yield:
18.3 g Al x 1 mol Al / 26.98 g x 2 mol AlI3 / 2 mol Al x 408 g AlI3/mol = 277 g AlI3