Inactive Tutor answered 12/03/21
a)
z = 2eiθ
z1/3 = 21/3eiθ/3 = 21/3(cos1/3(105°)+isin1/3(105°)
b)
r = √(25+9) = √34
tan-1(-3/5) = -30.96 --> θ=360-30.96 ≈ 329° = 1.8278π radians (Quadrant IV)
f(r,θ) = √34(cos(1.8278π)+isin(1.8278π)
MS S.
asked 12/03/21cube roots of 𝑧 in polar form where 𝑧=2(cos(105∘)+𝑖sin(105∘)).
Write the complex number 5−3𝑖 in polar form, 𝑟(cos(𝜃)+𝑖sin(𝜃)), with 𝑟>0,0≤𝜃≤2𝜋.
Inactive Tutor answered 12/03/21
a)
z = 2eiθ
z1/3 = 21/3eiθ/3 = 21/3(cos1/3(105°)+isin1/3(105°)
b)
r = √(25+9) = √34
tan-1(-3/5) = -30.96 --> θ=360-30.96 ≈ 329° = 1.8278π radians (Quadrant IV)
f(r,θ) = √34(cos(1.8278π)+isin(1.8278π)
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