Second fundamental thereom of calculus

Question

Use the chain rule to calculate f(x)=d/dx intergral with lower bound of 0 and upper bound of x^6 of ln(1+t^4) dt.

Please help I have no idea to where even begin for this problem.

Answer 1

the der, of the integral gives the original function back (since they are inverse operations)

but change the t to an x (or x^6 in this problem) thats from the other fundamental thm of calc) and then mult by the chain rule( derivative) of upper limit which =6x^5

so answer =

= ln[1+(x^6)^4]*(6x^5)