What is the equation of a line that passes through the point (-6,11) with slope -5/12 using point slope form?

Answer 1

Hello Andrew;

First, let's state that straight line is represented by the standard form y = mx + b where 'm' is the slope.

Let's plug the values given in the problem to the form.

y = 11, x = -6, m = -5/12 we just do not know 'b' which is the y-intercept

11 = -5/12 x (-6) + b

11=5/2 + b

b = 11 - 2.5 = 9.5 = 19/2

Then the equation is ready

y = (-5/12)x + 19/12 or expanded bby 12

5x + 12y = 19