a person x inches tall has a pulse rate approximately given by the function y=610x^-1/2. find the instantaneous rate of change for pulse rates at x=40 and x=70.

Answer 1

y=610x^(-1/2)

first find the first derivative of "y", this will be the instantaneous rate of change function

use the power rule

dy/dx= -305x^(-1.5)

to find the pulse rate use x=40 and x=70 in dy/dx

dy/dx=-305(40)^(-1.5) =