Inactive Tutor answered 11/29/21
a)
(r,θ)=(7,π/6)
rcos(θ)=7cos(π/6)=7√3/2
rsin(θ)=7sin(π/6) = 7/2
(x,y) = (7√3/2, 7/2)
b)
a+bi = -1 + i√3
r = √(a2+b2) = √4 = 2
θ = tan-1(b/a) = tan-1(√3/ -1) = 2π/3
(r,θ)=(2,2π/3)
Hey L.
asked 11/29/21Convert each of the following as indicated.
a) Convert from polar to rectangular coordinates:
(7,𝜋/6)
b.) Convert from rectangular to polar coordinates:
−1+√3𝑖
I need help with these problems, please!
Inactive Tutor answered 11/29/21
a)
(r,θ)=(7,π/6)
rcos(θ)=7cos(π/6)=7√3/2
rsin(θ)=7sin(π/6) = 7/2
(x,y) = (7√3/2, 7/2)
b)
a+bi = -1 + i√3
r = √(a2+b2) = √4 = 2
θ = tan-1(b/a) = tan-1(√3/ -1) = 2π/3
(r,θ)=(2,2π/3)
Inactive Tutor answered 11/29/21
pi/6 = 30 degrees. pi=180 degrees. 180/6 = 30
7 is the radius, the hypotenuse of a right triangle, where the opposite side = half the hypotenuse: 7/2 = 3.5
and the adjacent side is sqr3 times 7/2 = 3,5 sqr3 = about 3.5(1.732)
rectangular coordinates are (x,y) where x = 3.5sqr3 and y= 3.5
(x,y) = (3.5sqr3, 3.5)
-1 + sqr3 i is in 2nd quadrant. x coordinate is -1, y coordinate is isqr3. the angle formed has a reference angle of 60 degrees. Actual angle is 180-60 = 120 degrees = 2pi/3 radians
polar coordinates are (2, 2pi/3)
sqr3 and 1 are sides of a right triangle with hypotenuse = 2
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.