if you have 3.40 g of H2, how many grams of NH3 can be produced ?

Question

N2(g) + 3H2(g) ———> 2NH3(g)

if you have 3.40 g of H2, how many grams of NH3 can be produced ?

Answer 1

This question has been asked so many time, I can't even count. Here is my answer and explanation.

N₂(g) + 3H₂(g) ==> 2NH₃(g) ... balanced equation

We first convert 3.40 g of H₂ to moles of H₂. We then use the stoichiometry of the balanced equation to find the moles of NH₃ and finally convert moles of NH₃ back to grams of NH₃

molar mass H₂ = 2 g/mol

molar mass NH₃ = 17 g/mol

3.40 g H₂ x 1 mol H₂ / 2 g = 1.70 moles H₂

1.70 mols H₂ x 2 mols NH₃ / 3 mols H₂ = 1.13 moles NH₃

1.13 moles NH₃ x 17 g NH₃ / mol = 19.3 g NH₃ can be produced