NEED ASAP!! Use a right triangle to find the exact value of

Question

sin [ 2 sin^-1 ( √3 )]

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2

(its a fraction, √3 over 2)

Answer 1

sin^-1 √3 / 2 = π/3 This is a common reference angle

2 sin^-1 √3 / 2 = 2π/3

sin [2 sin^-1 √3 / 2] = √3 / 2

Look at a unit circle.

Answer 2

Based on what you show the sin^-1(sqrt3/2)=π/3

so it would be same as sin(2 times π/3) = sin(2π/3) = sqrt3/2

from the unit circle 2π/3 is the 2nd quadrant so it is positive