
William W. answered 11/28/21
Experienced Tutor and Retired Engineer
I believe you have a typo in your problem because the left side does not equal the right side.
Use the sum and difference identity:
to change the left side into:
[cos(α)cos(β) + sin(α)sin(β)]/sin(α)cos(β)
Then split the fraction into two parts (essentially go backwards from a single numerator divided by the common denominator into two separate fractions both having the common denominator):
[cos(α)cos(β)]/[sin(α)cos(β)] + [sin(α)sin(β)]/[sin(α)cos(β)]
Now cancel cos(β) from the top and bottom of the left fraction and cancel sin(α) from the top and bottom of the right fraction leaving:
cos(α)/sin(α) + sin(β)/cos(β)
Then substitute cos(α)/sin(α) = cot(α) and sin(β)/cos(β) = tan(β) leaving:
cot(α) + tan(β)