Kinetic Theory Calculations

Question

The rate of effusion of N₂ gas through a porous barrier is observed to be 9.94*10^-4 mol/h.

Under the same conditions, the rate of effusion of SO₂  gas would be  mol/h?

Answer 1

Graham's law of effusion

Rate gas 1 / Rate gas 2 = sqrt (MW gas 2 / MW gas 2)

gas 1 = N₂ (MW = 28 g/mol)

gas 2 = SO₂ (MW = 64 g/mol)

9.94x10^-4 mol/h / rate SO₂ = sqrt (MW SO₂ / MW N₂)

9.94x10^-4 / rate SO₂ = √(64/28)

9.94x10^-4 / rate SO₂ = 1.51

rate SO₂ = 9.94x10^-4 / 1.51

rate SO₂ = 6.58x10^-4 mol/h