Which of the following changes will increase the voltage of the cell Al(s)|Al3+(aq, 1.00 M )||Cu2+(aq,1.00 M)|Cu(s)?

Question

I. Increasing the surface area of the Al electrode

II. Decreasing the concentration of Al³⁺(aq) to 0.001 M

III. Decreasing the concentration of Cu²⁺(aq) to 0.001 M

Answer 1

Nernst equation:

Ecell = Eºcell + RT ln [Al³⁺]² / [Cu²⁺]³

So decreasing [Al³⁺] would decrease the voltage

So decreasing [Cu²⁺] would increase the voltage

I don't think changing the surface area should affect the voltage. It would affect the current I believe, but not the voltage. Not positive about this last point.